(b^3)^7/(b^2)^5=b^11

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Solution for (b^3)^7/(b^2)^5=b^11 equation: 


D( b )

(b^2)^5 = 0

(b^2)^5 = 0

(b^2)^5 = 0

1*b^10 = 0 // : 1

b^10 = 0

b = 0

b in (-oo:0) U (0:+oo)

((b^3)^7)/((b^2)^5) = b^11 // - b^11

((b^3)^7)/((b^2)^5)-b^11 = 0

0 = 0

b należy do R

b in (-oo:0) U (0:+oo)

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